Find the maximum possible force which can be applied to the 8 kg block shown in figure-2.94 to move both the blocks together if bottom surface is (a) frictionless, (b) having friction coefficient 0.3. Take `g = 10m//s^(2)`

A force of 100N is applied on a block of mass 3 kg as shown in the figure-2.164. The coefficient of friction between the surface and the block is 0.25.The frictional force acting on the block is: (Take g=10m/s^(2) )

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

The block is always at rest, the maximum force which can be applied for this is 24x. Find the value of x. Take g = 10 m//s^(2) {coefficient of friction = 0.3}

The block is always at rest, the maximum force which can be applied for this is 24x. Find the value of x. Take g = 10 m//s^(2) {coefficient of friction = 0.3}