In the circuit Fig. the value of beta is 200. Find `I_(B), V_(CE), V_(BE)` and `V_(BC)`, when `I_(C)=2.5mA`. The transistor is in active, cut off or saturation state.

In the circuit, the value of beta is 100. find I_B,V_(CE),V_(BE) and V_(BC) , when I_C =1.5mA. The transistor is in active, cut off or saturation state?

In the accompanying circuit (Fig. 5.9) the value of beta is 100 . Find I_(B),V_(CE),V_(CE) and V_(BC) , when I_(C) =1.5 mA . Is the transistor in active, cut-off or saturation state ?

In the common emitter circuit as shown in Fig, the value of the current gain is 100. Find I_(B),V_(CE),V_(BE),V_(BC) when I_(C)=1.5mA . The transistor is in active, cutoff or saturation state.

In the above circuit, I_(C) =1.5 mA and beta = 100.Find I_(B) , V_(CE) and V_(BE)

In the circuit shown in the figure, the input voltage V_i is 20 V, V_(BE) = 0 and V_(CE) = 0 . The values of I_B , I_C and beta are given by

In the circuit shows in the figure, the input voltage V_(i) is 20 V, V_(BE)=0 and V_(CE)=0 . The values of l_(B), l_(C) and beta are given by

In the circuit shown in Fig. when the input voltage of the base resistance is 10V, V_(be) is zero and V_(ce) is also zero. Find the values of I_, I_ and beta .

In the circuit shown in Fig. when the input voltage of the base resistance is 10V, V_(be) is zero and V_(ce) is also zero. Find the values of I_, I_ and beta .

In the circuit shown in the figure, the input voltage V_(i) is 20V, V_(BE)=0 and V_(CE) = 0 . The values of I_(B) , I_(C) and beta are given by