A double convex lens has two surfaces of equal radii R and refractive index m=1.5, we have

A double convex lens has two surfaces of equal radii R and refractive index n=1.5, we have

Two plano-convex lenses of radii of curvature R and R and refractive index 1.5 will have equivalent focal length equal to R, if they are placed

Two plano convex lens of radius of curvature R and refractive index n= 1.5 will have equivalent focal length equal to R when, they are placed :

A double convex lens has faces of radii of curvature 30 cm each. The refractive index of the material of the lens is 1.5. What is the focal length of this lens when immersed is carbondisulphide of refractive index 1.6 ?

A double convex lens is to be made of glass with refractive index. 1.5 One surface is to have twice the radius of curvature of the other surface and focal length is to be 60 mm. What are the radii ?

A thin douel convex lens has surfaces of radii of curature 30 cm each.Find the refractive index of the material of lens,if the focal length is 25 cm.

A double convex lens of + 5 D is made of glass of refractive index 1.5 with both faces of equal radii of curvature. Find the value of curvature.

A double convex lens of f = 6 cm is made of glass of refractive index 1.5. The radius of curvature of the surface which is double that of other surface will be

The radii of curvatures of a double convex lens are 15 cm and 30 cm, and its refractive index is 1.5. Then its focal length is -

A double convex lens has radii 20 cm.The refractive index of glass is 1.5.Compure the focal length of this lens in air and when immersed in carbon disulphide of refractive index = 1.63.