The tangent and normal to the ellipse `x^2+4y^2=4` at a point `P(theta`) on it meets the major axis in Q and R respectively. If `0

The tangent and normal to the ellipse x^(2)+4y^(2)=4 at a point P(theta) on it meets the major axis in Q and R respectively.If theta lt theta lt (pi)/(2) and QR=2 then show that theta=cos^(-1)((2)/(3)).

The tangent and normal to the ellipse x^(2)+4y^(2)=4 at a point P(theta) on it meet the major aixs in Q and R repectively. IF QR=2, then value of cos theta is/are

The tangent and normal to the ellipse x^(2) + 4y^(2) = 4 at a point P(0) on it meets the major axis in Q and R respectively. If 0lt (pi)/(2) and QR = 2 then show that theta = cos^(-1)(2/3) .

The tangent and normal to the ellipse 4x^(2)+9y^(2)=36 at a point P on it meets the major axis in Q and R respectively. If QR = 4, then the eccentric angle of P is

Assertion (A) If the tangent and normal to the ellipse 9x^(2)+16y^(2)=144 at the point P(pi/3) on it meet the major axis in Q and R respectively, then QR=(57)/(8) . Reason (R) If the tangent and normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))= at the point P(theta) on it meet the major axis in Q and R respectively, then QR=|(a^(2)sin^(2)theta-b^(2)cos^(2)theta)/(a cos theta)| The correct answer is

If the tangent and normal to the ellipse x^2 + 4y^2 = 4 at point P (theta) meets the major axes in Q and R respectively, and QR = 3 , then (A) cos theta = 1 /sqrt(3) (B) cos theta= 1/3 (C) cos theta = 2/3 (D) costheta = (-2/(3)

If the tangent and normal to the ellipse x^2 + 4y^2 = 4 at point P (theta) meets the major axes in Q and R respectively, and QR = 3 , then (A) cos theta = 1 /sqrt(3) (B) cos theta= 1/3 (C) cos theta = 2/3 (D) costheta = (-2/(3)

The tangent and the normal to the ellipse 4x^(2)+9y^(2)=36 at the point P meets the major axis Q and R respectively.If QR=4 then the eccentric angle of P is given by