Two protons are kept at a separation of `10 nm`. Let `F_n and F_e` be the nuclear force and the electromagnetic force between them.

Two protones are kept at a separation of 10 nm. Let F_(n) and F_(e) be the nuclear force and the elctromagnetic force between them .

Two proton are kept at a separation of 40Å.F_(n) is the nuclear force and F_(e) is the electrostatic force between them . Then

Two protons are kept at a separation of 50Å. Fn is the nuclear force and F_(e ) is the electrostatic force between them, then

The electrostatic force between two point charges and the gravitational attractive force between two point masses- both are inversely proportional to the square of the distance between the charges and the masses, respectively. (1)(a) Compare the eletrostatic force (F_(C)) and the gravitational force (F_(G)) between an electron and a proton. (b) Compare F_(C) and F_(G) between two protons. (ii) Find out the accelerations of an electron and of a proton due to the electrostatic force between them when htey are placed at a distance of 1 Å

Two nucleons are at a separation of one Fermi. Protons have a charge of +1.6 xx 10^(-19) C The net nuclear force between them is F_1 , if both are neutrons, F_(2) if both are protons and F_(3) if one is proton and the other is neutron. Then

The force of attraction between two bodies at certain separation is 10 N. What will be the force of attraction between them if the separation between them is reduced to half?

Force between two point electric charges kept at a distance of r in air is F. if these charges are kept at the same distance in water, how does the force between them change?

Let F_pp, F_pn and F_nn denote the magnitudes of the net force by a proton on a proton, by a proton on a neutron and by a neutron on a neutron respectively. Neglect gravitational force. When the separation is 1 fm ,

The force of attraction between two bodies at a certain separation is 10 N. What will be the force of attraction between them if the separation is reduced to half ?