The amount of energy released in the fusion of two `._(1)H^(2)` to form a `._(2)He^(4)` nucleus will be {Binding energy per nucleon of `._(1)He^(2)=1.1 MeV` Binding energy per nucleon of `._(2)He^(4)=7 MeV`]

Compute the binding energy per nucleon of ""_(2)^(4)"He" nucleus.

The binding energy per nucleon of _2He^4 is 7.075 MeV. What is its total binding energy?

The mass defect of He_(2)^(4) He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

In fusion reaction ._(1)H^(2) + ._(1)H^(2) to ._(2)He^(4) + Q Find the energy released while binding energy per nucleon for deuterium is 1.12 MeV and for helium nucleus is 7.07 MeV

The binding energy of ._(2)^(4)He is 28.57 MeV. What shall be the binding energy per nucleon of this element?

The mass defect of ""_(2)^(4)He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

Calculate the energy of the reaction , Li^(7) + p to 2 _(2)He^(4) If the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 MeV and 7.06 MeV , respectively .

The source of energy of stars is nuclear fusion. Fusion reaction occurs at very high temperature, about 10^(7) . Energy released in the process of fusion is due to mass defect. It is also called Q -value. Q = Delta mc^(2), Delta m = mass defect. The binding energy per nucleon of ._(1)H^(2) and ._(2)He^(4) are 1.1 MeV and 7 MeV , respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

The source of energy of stars is nuclear fusion. Fusion reaction occurs at very high temperature, about 10^(7) . Energy released in the process of fusion is due to mass defect. It is also called Q -value. Q = Delta mc^(2), Delta m = mass defect. The binding energy per nucleon of ._(1)H^(2) and ._(2)He^(4) are 1.1 MeV and 7 MeV , respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is