The opposite faces of a cubical block of iron of cross-section `4` square cm are kept in contact with steam and melting ice. Calculate the quantity of ice melted at the end of `10` minutes. `k` for iron `= 0.2 CGS` units.

The opposite face of a cubic block of iron of cross-section 8 sq.cm are kept in touch with steam and melting ice.Determine the quantity of ice melted at the end of 5 minutes (K=0.2 CGS units).

The opposite faces of a cubical block of iron and cross-section 4 sq. cm are kept in contact with steam of melting ice. Calculate the amount of ice melted at the end of 10 minutes if K = 0.2 cal cm^-1s^-1C^-1 for iron.

The opposite faces of a cubical block of iron of cross-section 4 xx 10^(-4) "m"^(2) are kept in contact with steam and melting ice. Calculating the amount of ice melted at the end of 5 minutes. Given K=0.2 cal cm ""^(-1) "s"^(-1)°"C"^(-1) .

One side of an iron plate one metre square is kept at 100°C and the other side is at 0°C. The thickness of the plate is 1 cm. If all the heat conducted across the plate in one minute is used in melting ice, calculate the amount of ice so melted. Thermal conductivity of iron = 0.162 in C.G.S. unit L.H. of fusion of ice = 80 cal/gm.

The two opposite faces of a cubical piece of iron (thermal conductivity = 0.2 CGS units) are at 100^(@)C and 0^(@)C in ice. If the area of a surface is 4cm^(2) , then the mass of ice melted in 10 minutes will b

The two opposite faces of a cubical piece of iron (thermal conductivity = 0.2 CGS units) are at 100^(@)C and 0^(@)C in ice. If the area of a surface is 4cm^(2) , then the mass of ice melted in 10 minutes will b

One end of metal bar of area of cross section 5cm^(2) and 25cm in length is in steam other in contact with ice, the amount of ice melts in one minute is (L_(ice) =80 cal//gm,K=0.8cgs" uits") .

A metal rod 25 cm long and 10sq cm in cross section has it's one end placed in boiling water and the other end in melting ice. Calculate the mass of ice method per minute if K for metal is 378 W/mk. Latent heat of fusion of ice - 80 K cal/gm . J = 4200 j/Kcal.