`int\ sec^2 theta(sec theta+tan theta)^2\ d theta`

int(sec theta)/(sec theta-tan theta)d theta

Evaluate the following w.r.t theta : int frac{sec theta }{sec theta + tan theta} d theta

int sec ^ (2) theta (sec theta + tan theta) ^ (2) dth eta

Prove the following identities: (sec-tan theta)/(sec theta+tan theta)=1-2sec theta tan theta+2tan^(2)theta

Simplify sectheta[(sec theta,tan theta),(tan theta,sec theta)]-tan theta[(tan theta, sec theta),(sec theta, tan theta)]

int(sec theta)/(tan^(2)theta)d theta is.

Prove that : (sec theta-tan theta)/(sec theta+tan theta)= 1-2 sec theta tan theta+ 2 tan^2 theta .

Simplify: tan theta[(sec theta, tan theta),(tan theta, -sec theta)] + sec theta[(- tan theta, -sec theta),(-sec theta, tan theta)] .

(tan theta)/(sec theta-1)+(tan theta)/(sec theta+1) is equal to 2tan theta(b)2sec theta(c)2cos ec theta(d)2tan theta sec theta