In `Delta ABC, if B=60^@,C=45^@` and D divides BC internally in the ratio `1:3` then `(sinangleBAD)/(sinangleCAD)`=

In a Delta ABC,/_B=60^(@) and /_C=45^(@). Let D divides BC internally in the ratio 1:3. then value of (sin/_BAD)/(sin/_CAD) is (A) sqrt((2)/(3)) (B) (1)/(sqrt(3)) (C) (1)/(sqrt(6)) (D) (1)/(3)

In a triangle ABC, angleB = pi/3 and angleC= pi/4 . Let D divide side BC internally in the ratio 1:3. Then sin(angleBAD)/sin(angleCAD) is

In triangle ABC, angle B = pi//3. " and " angle C = pi//4 . Let D divide BC inernally in the ratio 1 : 3 . Then (sin angle BAD)/(sin angle CAD) equals

In a triagnle ABC, angle B=pi/3 " and " angle C = pi/4 let D divide BC internally in the ratio 1:3 .Then (sin (angle BAD))/((Sin (angle CAD)) is equal to

In a triagnle ABC, angle B=pi/3 " and " angle C = pi/4 let D divide BC internally in the ratio 1:3 .Then (sin (angle BAD))/((Sin (angle CAD)) is equal to