A`Rh^-`mother carring a `Rh^-` child then :

Assertion : The defect callled erythroblastosis foetalis results if Rh-negative mother carreis a second Rh- position foetus. Reason : Replacement of the infanct's blood immediately after birth often cures the defect.

If a man Rh^(+) marries a loady Rh^(-) , then

After examining the blood group of husband and wife, the doctor advised them not to have more than one child, the blood group of the couple are likely to be: (a) Male Rh- and male Rh+ (b) Female Rh- and male Rh+ (c) Male Rh+ and female Rh+ (d) Male Rh- and female Rh-

If the foetus is Rh+ and mother is Rh^(-) then

The first child of Rh^(+) father and Rh^(-) mother is homozygous recessive condition. Is the next child affected by Erythroblastosis foctalis? Glven reason for your answer.

The Rh antibodies from the mother (Rh-ve) can leak into the blood of the foetus (Rh +ve) and destroy the :-

The Rh antibodies from the mother (Rh-ve) can leak into the blood of the foetus (Rh +ve) and destroy the :-

If the mother is Rh-ve and the father is Rh+ve, the condition of erythroblastosis foetalis may occur. This condition may be avoided by administrating anti - Rh antibodies to

A classical example of multiple alleles is found in Rh blood grouping of humans. Erythroblastosis fetalis occurs when mother is Rh^(+) and father is Rh^(-) .

If the mother is Rh-ve and the father is Rh+ve, the condition of erythroblastosis foetalis may occur. This condition may be avoided by administrating anti - Rh antibodies to