Find `alpha, a_(Q)` and the point of zero acceleration when the horizontal force `F` acts on the smooth rod of mass `m` and length `l` which is kept on a horizontal surface.

Find a_(C) and alpha of the smooth rod of mass m and length l .

Find a_(C) and alpha of the smooth rod of mass m and length l .

A uniform rod of mass m and length l is pivoted smoothly at point O as shown in figure. If a horizontal force F acts at the bottom of the rod and omega is the angular velocity of the rod which is a function of angle of rotation theta , then the maximum angular displacement of the rod is (Acceleration due to gravity, g)

A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m//s^(2) . And when the horizontal force is doubled, it gets an acceleration of 18 m//s^(2) . The coefficient of friction between the body and the horizontal surface is

A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m//s^(2) . And when the horizontal force is doubled, it gets an acceleration of 18 m//s^(2) . The coefficient of friction between the body and the horizontal surface is

A uniform rod of mass M and length L is standing vertically along the y -axis on a smooth horizontal surface as shown. A small disturbance causes the lower end to slip on the smooth horizontal surface and rod starts falling. The path followed by centre of mass of the rod during the fall is

A uniform rod of mass m and length l is pivoted smoothly at O . A horizontal force acts at the bottom of the rod. a. Find the angular velocity of the rod as the function of angle of rotation theta. b.What is the maximum angular displacement of the rod?