The random variable X has variance 4 and `E(x^(2))=8`, then the mean of x is

For a random variable X, E(X) = 3 and E(X^(2))=11 .Then variance of X is

If mu " and " sigma^(2) are the mean and variance of the discrete random variable X, and E(X+3)=10 and E(X+3)^(2)=116 , find mu " and " sigma^(2) .

Find probability distribution P(X) of random variable X if sum of mean and variance is 24 and their product is 128.

If the variance of the random variable X is 5 ,then variance of the random variable -3X is

For a random variable X, E(X)=3 and E(X^2)=11 Then, variance of X is

The probability distribution of a random variable X is given as under: given E(x)=2.94 Calculate variance of X.