Tangents PA and PB are drawn from P(a,b) to the circle `x^(2)+y^(2)=r^(2)`. The equation to the circum circle of `trianglePAB` is

If tangents PA and PB are drawn from P(-1, 2) to y^(2) = 4x then

If tangents PA and PB are drawn from P(-1, 2) to y^(2) = 4x then

Tangents PA and PB are drawn to x^2+y^2=a^2 from the point P(x_1, y_1)dot Then find the equation of the circumcircle of triangle P A Bdot

Tangents PA and PB are drawn to x^2+y^2=a^2 from the point P(x_1, y_1)dot Then find the equation of the circumcircle of triangle P A Bdot

The tangents PA and PB are drawn from any point P of the circle x^(2)+y^(2)=2a^(2) to the circle x^(2)+y^(2)=a^(2) . The chord of contact AB on extending meets again the first circle at the points A' and B'. The locus of the point of intersection of tangents at A' and B' may be given as

The tangents PA and PB are drawn from any point P of the circle x^(2)+y^(2)=2a^(2) to the circle x^(2)+y^(2)=a^(2) . The chord of contact AB on extending meets again the first circle at the points A' and B'. The locus of the point of intersection of tangents at A' and B' may be given as

Tangents PA and PB are drawn to the circle x^(2)+y^(2)=4, then locus of the point P if PAB is an equilateral triangle,is equal to

Tangents PA and PB are drawn from a point P to the circle x^(2)+y^(2)-2x-2y+1=0. If the point plies on the line lx+my+n=0 , where l,m,n are constants,then find the locus of the circum-Centre of the Delta PAB.