Calculate the enthalpy of formation of ammonia from the following bond enegry data:
`(N-H) bond = 389 kJ mol^(-1), (H-H) bond = 435 kJ mol^(-1)`, and `(N-=N)bond = 945.36kJ mol^(-1)`.

Calculate the enthalpy of formation of ammonia from the following bond energy data: (N-H) bond = 389 kJ mol^(-1), (H-H) bond = 435 kJ mol^(-1) , and (N-=N)bond = 945.36kJ mol^(-1) .

The enthalpy of formation of ammonia when calculated from the following bond energy data is (B.E. of N-H, H-H, N-=N is "389 kJ mol"^(-1), "435 kJ mol"^(-1),"945.36 kJ mol"^(-1) respectively)

The enthalpy of formation of ammonia when calculated from the following bond energy data is (B.E. of N-H, H-H, N-=N is "398 kJ mol"^(-1), "435 kJ mol"^(-1),"945.36 kJ mol"^(-1) respectively)

Using the bond enthalpy data given below, calculate the enthalpy of formation of acetone (g). Bond enegry C-H = 413.4 kJ mol^(-1) , Bond enegry C-C = 347.0 kJ mol^(-1) , Bond enegry C=O = 728.0 kJ mol^(-1) , Bond enegry O=O = 495.0 kJ mol^(-1) , Bond enegry H-H = 435.8 kJ mol^(-1) , Delta_("sub")H^(Theta)C(s) = 718.4 kJ mol^(-1)

Using the bond enthalpy data given below, calculate the enthalpy of formation of acetone (g). Bond enegry C-H = 413.4 kJ mol^(-1) , Bond enegry C-C = 347.0 kJ mol^(-1) , Bond enegry C=O = 728.0 kJ mol^(-1) , Bond enegry O=O = 495.0 kJ mol^(-1) , Bond enegry H-H = 435.8 kJ mol^(-1) , Delta_("sub")H^(Theta)C(s) = 718.4 kJ mol^(-1)

Find the enthalpy of formation of hydrogen flouride on the basis of following data: Bond energy of H-H bond =434 kJ mol^(-1) Bond energy of F-F bond =158 kJ mol^(-1) Bond enegry of H -F bond =565 kJ mol^(-1)

Find the enthalpy of formation of hydrogen flouride on the basis of following data: Bond energy of H-H bond =434 kJ mol^(-1) Bond energy of F-F bond =158 kJ mol^(-1) Bond enegry of H -F bond =565 kJ mol^(-1)

Calculate the enthalpy of formation of water, given that the bond energies of H-H, O=O and O-H bond are 433 kJ mol^(-1), 492 kJ mol^(-1) , and 464 kJ mol^(-1) , respectively.