If `(dy)/(dx)=(x-y+2)/(x-y+1),` where `u=x-y`, then

(dy)/(dx)=sin(x+y)+cos(x+y), where x+y=u

(x-y+1)(dy)/(dx)=x-y+2 , where x-y=u

1-(dy)/(dx)=sec(x-y)," where "x-y=u

(x(dy)/(dx)+y)sin(xy)=cosx, where xy=u

(x+y)(dx-dy)=dx+dy , where x+y=u

1+(dy)/(dx)=cos(x+y), where x+y=u

1+(dy)/(dx)=cos(x+y), where x+y=u

(dy)/(dx)=(y^(2)-y+1)/(x^(2)-x+1)

cos^(2)(x-2y)=1-2(dy)/(dx), where x-2y=u

Solve the following differential equation for a particular solution: y-x(dy)/(dx) = x+y (dy)/(dx) , where y=0 and x=1.