यदि `x^(2) + y^(2) + z^(2) = 20` व x + y + z = 0, तब सिध्द कीजिए xy + yz + zx = -10

If x^(2) + y^(2) + z^(2) - xy- yz - zx = 0 , prove that : x= y = z

If x^(2) + y^(2) + z^(2) = xy + yz + zx , then the triangle is :

Factorise : x^(2) + 4y^(2) + 25z^(2) - 4xy + 20 yz - 10 zx

If x^2 + y^2 + z^2 = xy + yz + zx , then the triangle is :

x+y-z=5 and x^(2)+y^(2)+z^(2)=29, find xy-yz-zx

If x+y -z = 4 and x^(2) + y^(2) + z^(2) = 30 , then find the value of xy- yz- zx

If x^(3) + y^(3) + z^(3) = 3xyz and x + y + z = 0 , find the value of : ((x+y)^(2))/(xy) + ((y+z)^(2))/(yz) + ((z+x)^(2))/(zx)