The velocity v and displacement r of a body are related as `v^(2) =kr`, where k is a constant. The acceleration of the body is

The velocity v and displacement r of a body are related by v^2 = kr where k is a constant. What will be velocity after 1 seconds.

The displacement of a body is given by 2 s= g t^(2) where g is a constant. The velocity of the body at any time t is :

If the velocity of a body related to displacement x is given by v=sqrt(5000+24x) m/s, then the acceleration of the body is _______ m//s^(2) .

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

If velocity of a particle is v=bs^(2) ,where b is constant and s is displacement. The acceleration of the particle as function of s is?

A body of mass m is thrown straight up with velocity v_(0)(v_(0) lt lt v_(e)) Find the velocity v with which the body comes down if the air drag equals kv^(2) , where k is a positive constant and v is the velocity of the body.

A body of mass m is thrown straight up with velocity v_(0)(v_(0) lt lt v_(e)) Find the velocity v with which the body comes down if the air drag equals kv^(2) , where k is a positive constant and v is the velocity of the body.