`sqrt((1+sinx)/(1-sinx))=tan(pi/4+x/2)`

Consider f(x)=tan^-1(sqrt((1+sinx)/(1-sinx)),x in(0,pi/2) . A normal to y=f(x) at x=pi/6 also passes through the point :

Differentiate tan^(-1){sqrt((1+sinx)/(1-sinx))}, -pi/2

If y=tan^(-1)sqrt(((1+sinx)/(1-sinx))),(pi)/(2)ltxltpi, then (dy)/(dx) equals to

Consider f(x)=tan^(-1)(sqrt((1+sinx)/(1-sinx))), x in (0,pi/2)dot A normal to y=f(x) at x=pi/6 also passes through the point:

tan^-1""sqrt((1+sinx)/(1-sinx))

Prove that, cosx/(1-sinx)=tan(pi/4+x/2)

Differentiate tan^(-1){sqrt((1+sinx)/(1-sinx))},\ -pi/2

Differentiate the following functions with respect to x : tan^(-1){sqrt((1+sinx)/(1-sinx))},-pi/2ltxltpi/ 2

It is given that, sqrt((1-sinx)/(1+sinx))=a- tan x , then a is equal to: यह दिया गया है कि sqrt((1-sinx)/(1+sinx))=a- tan x तो a किसके समान होगा?