Home
Class 12
PHYSICS
Figures shows an electric line of force ...

Figures shows an electric line of force which curves along a circular arc.The magnitude of electric field intensities is same at all points on this curve and is equal to `E`.If the potential at `A` is `V` ,the potential at `B` is

Promotional Banner

Similar Questions

Explore conceptually related problems

Figure shows electric lines of force. If E_(x) and E_(y) are the magnitudes of electric field at points x and y respectively, then

Electric field intensity is zero at a point. Is electric potential exist at the point?

Prove that the electric field intensity at a point is equal to the negative gradient of electric potential at that point.

The magnitude of electric field intensity at a point on the axis of short dipole is 30V/m. The distance of the point from the centre of the dipole is 2m. Then potential at that point is

Show that the electric field intensity at a point in an electric field is equal to the negative of the potential gradient of the field at that point. E = -(dV)/(dr)

Show that the electric field intensity at a point can be given as negative of potential gradient.

The magnitude of electric field intensity E is such that, an electron placed in it would experience an electrical force equal to its weight is given by