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If theta1 and theta2 are two values lyi...

If `theta_1` and `theta_2` are two values lying in `[0,2pi]` for which `t a ntheta=lambda,` then `tan((theta_1)/2)tan((theta_2)/2)` is equal to (a)0 (b) `-1` (c) 2 (d) 1

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