If the length of a simple pendulum is decreased by 3%, then the percentage error in its period T is

If the length of a simple pendulum is decreased by 2%, find the percentage error in its period T.

If the length of a simple pendulum is decreased by 2%, find the percentage decrease in its period T, where T = 2pi sqrt((l)/(g))

If length of a simple pendulum is increased by 69%, then the percentage increase in its time period is

If length of a simple pendulum is increased by 69%, then the percentage increase in its time period is

The length of a simple pendulum is decreased by 21% . Find the percentage change in its time period.

The length of a simple pendulum is decreased by 21% . Find the percentage change in its time period.

If the length of simple pendulum is increased by 21%, then its time period is

Assertion (A): If the length (l) of the simple pendulum is decreased by 4 % then decrease in its time period (T) is 2 % Reason (R) : If y=x^(n) , ratio of percentage errors in y and x is 1:n The correct answer is

If the length of a simple pendulum is increased by 45% what is the percentage increase in its time period?

The length of a simple pendulum is increased by 44%. The percentage increase in its time period will be