If the ratio of the roots of equation `ax^2+bx+c=0` be equal to that of the roots of `px^2+qx+r=0`, Prove that ,`rpb^2=caq^2`.

If the ratio of the roots of the equation ax^(2)+bx+c=0 is m: n then

If the ratio of the roots of the equation ax^(2)+bx+c=0 is m: n then

If the roots of the equation ax^2+bx+c=0(a!=0) be equal then

The roots of the equation ax^2+bx+c=0 are equal when-

If the roots of the equation ax^(2)+bx+c=0 are equal then c=?

If the roots of the equation ax^(2)+bx+c=0(ane0) be equal, then

If the ratio of the roots of a(x)^2+bx +c=0 is same as that of the roots of px^2 +qx+r=0 then a//p,b//q,c//r are in

If the ratio of the roots of the equation ax^2+bx+c=0 is equal to ratio of roots of the equation x^2+x+1=0 then a,b,c are in

If the ratio of the roots of the equation x^(2)+px+q=0 are equal to ratio of the roots of the equation x^(2)+bx+c=0, then prove that p^(2c)=b^(2)q

If the ratio of the roots of the equation ax^(2)+bx+c=0 is equal to ratio of roots of the equation x^(2)+x+1=0 then a,b,c are in