Home
Class 12
CHEMISTRY
Two electrochemical cells are assembled ...

Two electrochemical cells are assembled in which the following reactions occur `:`
`V^(2)=VO^(2+)+2H^(o+)rarr 2V^(3+)+H_(2)O`
`V^(3+)+Ag^(o+)+H_(2)O rarr VO^(2+)+2H^(o+)+Ag(s)`
Calculate `E^(c-)` for half reaction `V^(3+)+e^(-)rarr V^(2+)`
Given `: E^(c-)._((Ag^(o+)|Ag))=0.799`
`E^(c-)=E^(c-)._(V^(4+)|V^(3+))-E^(c-)._(V^(3+)|V^(2+))=0.616V`
`E^(c-)=E^(c-)._(Ag^(o+)|Ag)-E^(c-)._(V^(4+)|V_(3+))=0.439V`

Promotional Banner

Similar Questions

Explore conceptually related problems

Two electrochemical cells are assembled in which the following reaction occur. V^2+VO^2+2H^+ to 2V^3+H_2O, E_(cell) ^@=0.616V V^3+Ag^+ +H_2O to VO^2+2H^+ + Ag(s), E_(cell)^@=0.439V calculate E^@ for the half cell reaction V^(3+) +e to V^(2+) (E_(Ag)^@, Ag=0.799 volt )

Given E^(c-)._(Ag^(o+)|Ag)=+0.80V, E^(c-)._(Co^(2)|Co)=-0.28V, E^(c-)._ (Cu^(2+)|Cu)=+0.34V E^(c-)._(Zn^(2+)|Zn)=-0.76V Which metal will corrode fastest ?

Given E^(c-)._(Ag^(o+)|Ag)=+0.80V,E^(c-)._(Co^(2)|Co)=-0.28V, E^(c-)._(Cu^(2+)|Cu)=+0.34V,E^(c-)._(Zn^(2+)|Zn)=-0.76V Which metal will corrode fastest ?

Find the equilibrium constant for the reaction : Cu^(2+)+In^(2+)hArrCu^(o+)+In^(3+) Given that E^(c-).._(Cu^(2+)|Cu^(o+))=0.15V,E^(c-)._(ln^(2+)|ln^(o+))=-0.4V, E^(c-)._(ln^(3+)|ln^(o+))=-0.42V

K_(d) for dissociation of [Ag(NH_(3))_(2)]^(+) into Ag^(+) and NH_(3) is 6 xx 10^(-8) . Calculae E^(@) for the following half reaction. Ag(NH_(3))_(2)^(+) +e^(-) rarr Ag +2NH_(3) Given Ag^(+) +e^(-) rarr Ag, E^(@) = 0.799V

Dissociation constant for Ag(NH_(3))_(2)^(+) into Ag^(+) and NH_(3) is 6 xx 10^(-14) . Calculate E^(@) for the half reaction. Ag(NH_(3))_(2)^(+) + e rarr Ag + 2NH_(3) Given, Ag^(+) + e rarr Ag has E^(@) = 0.799 V

Dissociation constant for Ag(NH_(3))_(2)^(+) into Ag^(+) and NH_(3) is 6 xx 10^(-14) . Calculate E^(@) for the half reaction. Ag(NH_(3))_(2)^(+) + e rarr Ag + 2NH_(3) Given, Ag^(+) + e rarr Ag has E^(@) = 0.799 V

Ag^(+) + e^(-) rarr Ag, E^(0) = + 0.8 V and Zn^(2+) + 2e^(-) rarr Zn, E^(0) = -076 V . Calculate the cell potential for the reaction, 2Ag + Zn^(2+) rarr Zn + 2Ag^(+)