Refractive index mu is given as `mu=A+B/lambda^2,` where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

The refractive index of a medium is given by mu=A+(B)/(lambda^(2)) where A and B are constants and lambda is the wavelength of light. Then the dimensions of B are the same as that of

The refractive index ( mu ) of glass is related to the wavelength (lambda) of incident light as mu = A +(B)/(lambda^(2)) , where A and B are constants. Find out the dimensions of A and B.

When white light travels through glass the refractive index mu=(velocity of light in air/velocity of light in glass) is found to very with waveless as mu=A+B/lambda^2 where A and B are constants. Using the principle of homogeneity of dimensions, determine the SI unit in which A and B must be expressed.

(i) mu=(c)/(v_m)=(vlambda)/(vlambda_m) where c: speed of light in vacuum v_m: speed of light in medium lambda: wavelength in vacuum lambda_m : wavelength in medium upsilon: frequency of light (ii) mu=((epsilonmu)/(epsilon_0mu_0))^(1/2) where epsilon: electric permittivity in free space epsilon: electric permittivity in medium mu_0: magnetic permeability in free space mu: magnetic permeability in medium (iii) mu=A+B/lambda^2 , where A and B are constants (iv) In case of VIBGYOR, wavelength increases from violet to red, refractive index decreases from violet to red. Wavelength for red-colour is maximum whereas refractive index is maximum for violet colour.

The momentum of an electron in an orbit is h//lambda , where h is a constant and lambda is wavelength associated with it. The nuclear magneton of electron of charge e and mass m_(e) is given as mu_(n)=(eh)/(3672 pim_(e)) . The dimension of mu_(n) are (Ararr"current")

The angles of incidence and refraction of a monochromatic ray of light of wavelength lamda at an air-glass interface are i and r, respectively. A parallel beam of light with a small spread delta lamda in wavelength about a mean wavelength lamda is refracted at the same air-glass interface. The refractive index mu of glass depends on the wavelength lamda as mu(lamda) = a + b//lamda2 where a and b are constants. Then the angular spread in the angle of refraction of the beam is

The angles of incidence and refraction of a monochromatic ray of light of wavelength lamda at an air-glass interface are i and r, respectively. A parallel beam of light with a small spread delta lamda in wavelength about a mean wavelength lamda is refracted at the same air-glass interface. The refractive index mu of glass depends on the wavelength lamda as mu(lamda) = a + b//lamda2 where a and b are constants. Then the angular spread in the angle of refraction of the beam is