`lim_(x to0) ((1+a^(3))+8e^(1//x))/(1+(1-b^(3))e^(1//x))=2 " then "-`

underset(x to0)(lim)((1+a^(3))+8e^(1//x))/(1+(1-b^(3))e^(1//x))=2 then value of a and b are?

If lim_(x rarr oo)((1+a^(3))+8e^((1)/(x)))/(1+(1-b^(3))e^((1)/(x)))=2, then there

If lim_(x->oo)((1+a^3)+8e^(1/ x))/(1+(1-b^3)e^(1/ x))=2, then there exists

If ("lim")_(xvec0)((1+a^3)+8e^(1/x))/(1+(2+b+b^2)e^(1/x))=2, where a ,b in R , then the possible ordered pair (a,b) is (2,-2) (b) (1,-2) (1,1) (d) (-1,1)

lim_(x rarr 0^+)(x e^(1//x))/(1+e^(1//x))=

If lim_(x to 0)x^((1)/(1-x))=e^(-1)

lim_(x rarr0)((1+2x)/(1+3x))^((1)/(x^(2))*e^((1)/(x))is=)