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A 150 mL of solution of I(2) is divided ...

A 150 mL of solution of `I_(2)` is divided into two unequal parts. I part reacts with hypo solution solution in acidic medium. 15 mL of 0.4 M hypo was consumed. II part was added with 100 mL of 0.3 MNaOH solution. What was the initial concentration of `I_(2)` ?

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A 150 mL of solution of I_(2) is divided into two unequal parts. I part reacts with hypo solution solution in acidic medium. 15 mL of 0.4 M hypo was consumed. II part was added with 100 mL of 0.3 M NaOH solution. Residual base required 10 mL 0.3 M H_2SO_4 solution for complete neutralization. What was the initial concentration of I_(2) ?

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