The escape velocity of a body from the surface of the earth is equal to

The escape velocity of a body from the surface of the earth is nearly

The escape velocity of a body from the surface of earth is

The escape velocity of a body from the surface of the earth is V_e and the escape velocity of the body from a satellite orbiting at a height 'h' above the surface of the earth is v_e ' then

The escape velocity of a body from the surface of the earth is V_e and the escape velocity of the body from a satellite orbiting at a height 'h' above the surface of the earth is v_e ' then

The escape velocity of a body from the surface of the earth is V_(1) and from an altitude equal to twice the radius of the earth, is, V_(2) . Then

The escape velocity of a body from the surface of the earth is expressed in terms of density and diameter of the earth, it is found that it is

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .