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সমাধান করো : ydy/dx=xe^(x^2+y^2)...

সমাধান করো : `ydy/dx=xe^(x^2+y^2) `

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y(dy)/(dx)=xe^(x^(2)+y^(2))

y(dy)/(dx)=xe^(x^(2)+y^(2))

int xe^(x^2) dx

int xe^(x^2+2)dx

int xe^(x^2+2)dx

e^ydy/dx + x^3cosx^2 = 0

The general solution of dy/dx = 2xe^(x^(2)-y) is

ydy+xe^(x)cos^(2)ydx=0

The general solution of (dy)/(dx)=2xe^(x^(2)-y) is