The displacement (x) and time (t) for particle are related as `t=sqrt(x)+3`. What is the work done in te first six sexond of its motion?

The displacement x and time t for a particle are related to each other as t-3=sqrt x . What is work done in first six seconds of its motion.

If the displacement of a particle varies with time as sqrt(x) = t + 7 . The -

Displacement x in metre and time t in second are related as t=sqrt(x)+3 , for a particle of mass 1g moving in a straigh line. (ii) What is the work done in the first 6 s of motion ?

If the displacement of a particle varies with time as sqrt x = t+ 3

If the displacement of a particle varies with time as sqrt x = t+ 3

Displacement x and time t, in a rectiIinear motion of a partical are reIated as t = sqrt(x)+3 . Here x is measured in metre and t in second. Find the displacement of the partical when its velocity is zero.

Displacement (x) and time (t) of a particle in motion are related as x = at + bt^(2) -ct^(3) where a,b, and c, are constants. Velocity of the particle when its acceleration becomes zero is

The displacement x (in m ) and time t (in s) of a particle are connected by the relation sqrt(t + 3 + x) = 2 , then: