Home
Class 12
PHYSICS
From the relation R=R(0)A^(1//3), where ...

From the relation `R=R_(0)A^(1//3)`, where `'R_(0)'` is a constant and 'A' is the mass number of a nucleus, show that the nuclear matter density is nearly constant.

Promotional Banner

Similar Questions

Explore conceptually related problems

From the relation R = R_0A^(1//3) , where R_0 is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e. independent of A).

from the relation R=R_0A^(1//3) , where R_0 is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e., independent of A ).

From the relation R = R_0A^(1/3) , where R_0 is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e. independent of A).

From the relation R=R_0A^(1/3) , where R_0 is a constant and A is the mass number of a nucleus , show that the nuclear matter density is nearly constant.(i.e., independent of A)

form the relation R=R_0A^(1//3) , where R_0 is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e., independent of A ).

From the relation R = RoA^(1/3) Where R_0 is a constant and A is the mass number of a nucleus show that the nuclear matter density is nearly constant (.e. Independent of A)

R=R_(0)A^(1//3) , where R_(0) has the value:

Atomic nucleus is central core of every atom in which the whole of positive charge and almost entire mass of atom is concentrated. It is a tiny sphere of a radius R is given by R=R_(o)A^(1//3) , where R_(o)=1.4xx10^(-15)m , a constant and A the mass number of nucleus The radius of the nucleus of mass number 125 is