`(dy)/(dx)` का मान ज्ञात कीजिए-
`y=e^(x+e^(x+e^(x+….oo)))`

dy/dx का मान ज्ञात कीजिए यदि x=2at,y=at^2

(dy)/(dx) =y ((e^(3x)-e^(-3x))/(e^(3x) +e^(-3x)))

Find (dy)/(dx) if y=e^(x)*e^(x^(2))*e^(x^(3))*e^(x^(4))

y= e^(x+ e^(x+ e^(x+ ....oo))) then find (dy)/(dx)

If y = e ^(x + e ^(x + e^(x ...oo))), then (dy)/(dx)=

If y = e^(x^(e)) then dy/dx =

If e^(x) + e^(y) = e^(x + y) , then prove that (dy)/(dx) = (e^(x)(e^(y) - 1))/(e^(y)(e^(x) - 1)) or (dy)/(dx) + e^(y - x) = 0 .

If y=e^(x)+e^(-x)," then: "(dy)/(dx)=

If y=e^(x)+e^(-x)," then: "(dy)/(dx)=