The equation `2x^(2)-3xy-py^(2)+x+qy-1=0` represent two mutually perpendicular lines if

The equation 2x^2+4xy-py^2+4x+qy+1=0 will represent two mutually perpendicular straight lines , if

The equation 2x^2+4xy-py^2+4x+qy+1=0 will represent two mutually perpendicular straight lines , if

If 2x^(2)+4xy-py^(2)+4x+qy+1=0 represents a pair of mutually perpendicular lines then

If equation 8x^(2)-3xy+lamday^(2)=0 represents two mutually perpendicular lines, then lamda=

Prove that the equation 2x^(2)+3xy-2y^(2)+3x+y+1=0 represents a pair of perpendicular lines and find the lines.

If the equation 12x^(2)+7xy-py^(2)-18x+qy+6=0 represents a pair of perpendicular lines then

If the equation 12x^2 + 7xy - py^2 - 18x qy + 6 = 0 represent two perpendicular lines, then the value of p and q are :

If the equation 2x^(2)-3xy-py^(2)+x+qy-1=0backslash(p,q in I) represents two mutually perpendicular lines, then (A) p^(2)+q^(2)=13 (B) p-q=5(C)p^(2)-q^(2)=1(D)p+q=5