The maximum velocity of photoelectronos emitted hy a photoemitter is `1.8 xx 10^(6) m//sec`. Taking `e//m = 1.8 xx 10^(11) C/kg` for electrons, the stopping potential of the emitter is:

Maximum velocity of the photoelectron emitted by a metal is 1.8 xx 10^(6) ms^(-1) . Take the value of specific charge of the electron is 1.8 xx 10^(11) C kg^(-1) . Then the stopping potential in volt is

Maximum velocity of photoelectrons emitted by a metal surface is 1.2xx10^(6)m//s . Assuming the specific charge of the electrons to be 1.8xx10^(11)C//kg the value of stopping potential in volt will be:

Maximum velocity of photoelectrons emitted by a metal surface is 1.2xx10^(6)m//s . Assuming the specific charge of the electrons to be 1.8xx10^(11)C//kg the value of stopping potential in volt will be:

Maximum velocity of photo electrons is 3.5 xx 10^(6) m//s . If the specific charge of an electron is 1.75 xx 10^(11) C/kg, stopping potential of the electron is

The maximum velocity of ejected photoelectrons 2 xx 10^6 m/sec and (e/m) of electrons is 1.8 xx 10^11 coul/kg. The stopping potential in volts is

A photoelectron is moving with a maximum velocity of 10^(6) m//s . Given e=1.6xx10^(-19) c , and m=9.1xx10^(-31) kg , the stopping potential is