Home
Class 12
MATHS
वक्र के लिए निर्दिष्ट बिन्दु पर स्पर्श र...

वक्र के लिए निर्दिष्ट बिन्दु पर स्पर्श रेखा और अभिलम्ब कि प्रवणता ज्ञात कीजिए-
`x=a (theta -sin theta), y=a (1-cos theta) , theta =(pi)/(2)`पर

Promotional Banner

Similar Questions

Explore conceptually related problems

x=a(theta-sin theta), y= a (1+cos theta) find (dy)/dx "at " " " theta=pi/2 .

If x=a(theta-sin theta) and,y=a(1+cos theta) find (dy)/(dx) at theta=(pi)/(3)

If x =theta -sin theta ,y=1 -cos theta ,then " at " theta =(pi)/(2) ,(dy)/(dx) =

If x=a (theta-sin theta) and y=a(1-cos theta) , find (d^(2)y)/(dx^(2)) at theta=pi.

If x=a ( theta - sin theta), y =a (1 - cos theta) then y _(2) at theta = pi //4 is

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

The length of normal to the curve x=a(theta+sin theta), y=a(1-cos theta), at theta=(pi)/(2) is

The length of normal to the curve x=a(theta+sin theta), y=a(1-cos theta), at theta=(pi)/(2) is

Find the length of normal to the curve x=a(theta+sin theta),y=a(1-cos theta) at theta=(pi)/(2)