Two very small particles are executing `SHM` along very near parallel lines about the same mean position, same amplitude and the same frequency. At `t = 0` both the particle are moving with speed of `1m//sec` but on the opposite side of the mean position and having same direction of velocity at a distance of `5cm` from the mean position. At `t = 4sec` they are at the same position moving with speed of `1m//sec` but in opposite direction. Assuming that this is the minimum time form `t = 0` where they are meeting for the `1st` time. If the maximum speed of either particle is `(xpi)/(4sqrt(2))cm//sec` Find `x`