In an `LC` circuit the capacitor has maximum charge `q_0`. The value of `((dI)/(dt))_(max)` is

An LCR circuit is equivalent to a damped pendulam. In an LCR circuit the capacitor is charged to Q_0 and then connected to the L and R as shown below: If the students plots graphs of the square of maximum charge (Q_(max)^2) on the capacitor with time (t) for two different values L_1 and L_2(L_1gtL_2) of L then which of the following represents this graph correctly?(plots are schematice are not drawn to scale)

An LCR circuit is equivalent to a damped pendulum. In an LCR circuit the capacitor is charged to Q_0 and then connected to the L and R as shown below: If a student plots graphs of the square of maximum charge (Q_"Max"^2) on the capacitor with time (t) for two different values L_1 and L_2 (L_1 gt L_2) of L then which of the following represents this graph correctly ? (plots are schematic and not drawn to scale)

In LC circuit the maximum charge in capacitor is q_0 . Then maximum value of rate of change of current is

In LC circuit the maximum charge in capacitor is q_0 . Then maximum value of rate of change of current is

An LC circuit oscillating at natural frequency conssts of an inductor of inductance 30 m H and a capacitor of capacitance 60 muF . The maximum value of instantaneous charge on capacitor in the circuit is 250 mu C . If I is the current in the circuit then answer the following : (i) What is the value of (dI)/(dt) when charge is 150 mu C? (ii) Calculate the value of I when charge is 200 muC . (iii) Find the maximum value of I. (iv) For what value of q I is half of its maximum value ?

In the given LC circuit,if initially capacitor C has charge Q on it and 2C has charge 2Q. The polar ar as shown in figure. Then after closing switch S and t=0