Three vertices are chosen from the vertices of a regular hexagon, then the probability that they will form an equilateral triangle is

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle has exactly one side common with the side of the hexagon is

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle with these vertices is an equilateral triangle is equal to

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle has exactly two sides common with the side of the hexagon is

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle has exactly two sides common with the side of the hexagon is

If three vertices of a regular hexagon are chosen at random, then the chance that they form an equilateral triangle is :

Three vertices are chosen randomly from the seven vertices of a regular 7 -sided polygon. The probability that they form the vertices of an isosceles triangle is

Three vertices are chosen randomly from the seven vertices of a regular 7 -sided polygon. The probability that they form the vertices of an isosceles triangle is

Three vertices are chosen randomly from the seven vertices of a regular 7 -sided polygon. The probability that they form the vertices of an isosceles triangle is

Three vertices are chosen randomly from the seven vertices of a regular 7 -sided polygon. The probability that they form the vertices of an isosceles triangle is