A particle moves along a line according to the law `s(t)=2t^(3)-9t^(2)+12t-4`, where `tge0`.
At what times the particle changes direction?

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the particle's acceleration each time the velocity is zero.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

A particle moves along x-axis according to the law x=(t^(3)-3t^(2)-9t+5)m . Then :-

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle moves along a line according to the law s=4t^3-3t^2+2 . At what time will the acceleration be equal to 42 unit/ sec^2 ?

A particle moves along a straight line according to the law s=16-2t+3t^(3) , where s metres is the distance of the particle from a fixed point at the end of t second. The acceleration of the particle at the end of 2s is

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves along a straight line according to the law s=t^3/3 -3t^2+9t+17 , where s is in meters and t in second. Velocity decreases when