There is a `5 Omega` resistance in an `AC`, circuit. Impedence of `0.1 H` is connected with it in series. If equation of `AC` emf is `5 sin 50 t` then the phase difference between current and e.m.f. is

There is a 5 Omega resistance in an AC , circuit. Inductance of 0.1 H is connected with it in series. If equation of AC emf is 5 sin 50 t then the phase difference between current and e.m.f. is

An alternating e.m.f. 100 cos 100 t volt is connected in series to a resistance of 10 ohm and inductance 100mH. The phase difference between the current in the circuit and the e.m.f. is

An alternating e.m.f. 100 cos 100 t volt is connected in series to a resistance of 10 ohm and inductance 100mH. The phase difference between the current in the circuit and the e.m.f. is

A pure inductance is connected to an AC source. What will be the phase difference between the current and the EMF in the circuit?

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be