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Excess of solid AgCl is added to a 0.1 M...

Excess of solid `AgCl` is added to a `0.1 M` solution of `Br^(c-)` ions. `E^(c-)` for half cell is `:`
`AgBr+e^(-) rarr Ag+Br^(c-),E^(c-)=0.095V`
`AgCl+e^(-) rarr Ag+Cl^(c-), E^(c-)=0.222V`
The value of `[Br^(c-)]` ion at equilibrium is `:`
`[` Given `: Antilog (2.152)=142]`

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