A detergent `(C_(12)H_(25)SO^(4)^(-)Na^(+))` solution becomes colloidal sol at a concentration of `10^(-3)`M . On an average `10^(13)` colloidal partcles are present in `1mm^(3)` . What is the average number of ions which are contained by one colloidal particle (micelle)?

A detergent (C_(12)H_(23)SO_(4)^(-)Na^(+)) solution becomes a colloidal sol at a concentration of 10^(-3) M.On an average 10^(13) colloidal particles are present in 1 mm^3 What is the average number of ions are contain in one colloidal particle (micelle)? [Given : N_A = 6 xx 10^(23)]

A detergent C_2H_2 solution becomes a colloidal sol at a concentration of 10^3 M On an average 10^33 colloidal particles are present in 1mn^3 What is the average number of ion are contain in one colloidal particle (micelle)? [Given NA=6 diamond ^2 ]

A detergent (C_(12)H_(25)SO_(4)Na) solution becomes a colloidal solution at a concentration of 10^(-3) mol/lit. On an average 10^(13) colloidal particles are present in 1 mm^(3) what is average number is C_(12)H_(25)SO_(4)Na in one colloidal particle ?

A detergent [C_12 H_2SO_(4)^(-) Na^(+)] solution becomes a colloidal sol at a conc. of 10^(-3)M on an average 10^13 colloidal particles are present in lmm what is the average no.of ions are contain in one colloidal particle (micelle) no.of ions 6 x 10^x . x is .......

Calculate the concentration of H^(+) ion in 5times10^(-1)M solution of H_(2)SO_(4)

When 25 g of Na_(2)SO_(4) is dissolved in 10^(3) Kg of solution, its concentration will be

When 25 g of Na_(2)SO_(4) is dissolved in 10^(3) Kg of solution, its concentration will be