A charge Q is divided into two equal parts `q=(Q)/(2)`. If the chages q and q are placed at certain distance,

A certain charge 2Q is divided at first into two parts q_(1) and q_(2) . Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then Q/(q_(1)) = ________.

A certain charge Q is divided at first into two parts, q and Q-q. later on the charges are placed at a certain distance. If he force of interaction between two charges is maximum, then

A certain charge Q is divided into two parts q and Q-q , which are then separated by a certain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A certain charge Q is divided into two parts q and Q-q , wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A certain charge Q is divided into two parts q and Q-q , wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A certain charge Q is divided into two parts q and Q-q , wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A certain charge Q is divided into two parts q and (Q–q). How should the charges Q and q be divided so that q and (Q–q) placed at a certain distance apart experience maximum electrostatic repulsion ?

A certain charge Q is divided into two parts q and (Q-q). How Q and q be related such that when q and (Q-q) are placed certain distance apart, they experience maximum repulsion?