Let `f(x)={((x^3+x^2-16x+20))/((x-2))^2, if x != 2 and k, if x=2.` If `f(x)` is conti-nuous for all `x,` then `k=`

f(x)={((x^(3)+x^(2)-16x+20))/(((x-2))^(2)),quad if x!=2 and k,quad if x=2 If f(x) is conti-nuous for all x, then k=

Let f(x) ={{:((x^(3)+x^(2)-16x+20)//(x-2)^(2)"," if x ne 2),(R", "if x = 2):} If f(x) is continuous for all x, then k = … .

Let f(x) = {((x^(3)+x^(2)-16x+20)/((x-2)^(2)), ",","if" x != 2),(k, ",", "if" x = 2 ):} . If f(x) is continuous for all x, then k =

If f(x)=( x^3+x^2-16x + 20)/(x-2)^2 if x!=2 = k if x = 2 is continuous at for all x, then what is the value of k.

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2 and k, if x=2 at x=2

Let f(x)={{:((x^(3)+x^(2)-16x+20)/((x-2)^(2)),"when " xne2),(" "k,"when " x=2):} if f (x) is continuous for all x , find k.