Home
Class 11
PHYSICS
Two very small particles are executing S...

Two very small particles are executing `SHM` along very near parallel lines about the same mean position, same amplitude and the same frequency. At `t = 0` both the particle are moving with speed of `1m//sec` but on the opposite side of the mean position and having same direction of velocity at a distance of `5cm` from the mean position. At `t = 4sec` they are at the same position moving with speed of `1m//sec` but in opposite direction. Assuming that this is the minimum time form `t = 0` where they are meeting for the `1st` time. If the maximum speed of either particle is `(xpi)/(4sqrt(2))cm//sec` Find `x`

Promotional Banner

Similar Questions

Explore conceptually related problems

When a particle executing a linear S.H.M. moves from its extreme position to the mean position, its

When a particle executing a linear S.H.M. moves from its extreme position to the mean position, its

A particle performing linear S.H.M. with period 6 second ,is at the positive extreme position at t = 0. The particle is found to be at a distance of 3 cm from the extreme position at time t = 7 sec, before reaching the mean position. Find the amplitude of the S.H.M.

The particle performing S.H.M. along a straight line about the mean position with an amplitude 'A'. Then the maximum potential energy at a distance A from the extreme position is

Two particle undergoes SHM along parallel line with the same time period (T) and equal amplitude At a particular instant , one particle is at its extereme position while the other is at its mean position .They move in the same direction .They will cross each other after a further time

Two particles execute S.H.M. along the same line at the same frequency. They move in opposite direction at the mean position. The phase difference will be :

Two particles A and B oscillates in SHM having same amplitude and frequencies f_(A) and f_(B) respectively. At t=0 the particle A is at positive extreme position while the particle B is at a distance half of the amplitude on the positive side of the mean position and is moving away from the mean position.

Two particles A and B oscillates in SHM having same amplitude and frequencies f_(A) and f_(B) respectively. At t=0 the particle A is at positive extreme position while the particle B is at a distance half of the amplitude on the positive side of the mean position and is moving away from the mean position.

Two particles undergo SHM along parallel lines with the same time period (T) and equal amplitudes. At particular instant, one particle is at its extreme position while the other is at its mean position. The move in the same direction. They will cross each other after a further time.