Home
Class 12
CHEMISTRY
Two liquids A and B are mixed to form an...

Two liquids A and B are mixed to form an ideal solution. The totol vapour pressure of the solution is 800 mm Hg. Now the mole fractions of liquid A and B are interchanged and the total vapour pressure becomes 600 mm of Hg. Calculate the vapour pressure of A and B in pure form. (Given :`p_(A)^(@)-p_(B)^(@)=100`)

Promotional Banner

Similar Questions

Explore conceptually related problems

The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour pressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-

The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour [ressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-

Two liquids A and B form an ideal solution. The ratio of vapour pressures of pure liquids A and B are 3: 5. If the mole fraction of A in the liquid solution at equilibrium with vapours is 0.4, then the mole-fraction of B in the liquid is

If P_(A) is the vapour pressure of a pure liquid A and the mole fraction of A in the mixture of two liquids A and B is x, the parial vapour pressure of A is:

If P_(A) is the vapour pressure of a pure liquid A and the mole fraction of A in the mixture of two liquids A and B is x, the parial vapour pressure of A is:

The vapour pressure of pure liquids A and B are 450 mm Hg and 700 mm Hg, resprectively at 350 K. Find the composition of liquid and vapour if total vapour pressure is 600 mm. Hg.