The random variable takes the values 1,2,3,…….m. If `P(X=n)=(1)/(m)` to each n, then the variance of X is

A random variable X takes the values 0,1 and 2. If P(X=1)=P(X=2) and P(X=0)=0.4 then the mean of the random variable X is

Gien that X is discrete random variable which take the values, 0,1,2 and P(X=0)=(144)/(169),P(X=1)=(1)/(169) , then the value of P(X=2) is

A random variable X takes the values 0,1 and 2 .If P(X=1)=P(X=2) and P(X=0)=0.4 ,then the mean value of the random variable X is

A random variable X takes the values 0,1,2, it's mean is 0.6. If P(X=0)=0.5 then P(X=1)=

A random variable X takes the values 0,1,2,3,..., with prbability P(X=x)=k(x+1)((1)/(5))^x , where k is a constant, then P(X=0) is.

A random variable X takes the values 0,1,2,3,..., with prbability P(X=x)=k(x+1)((1)/(5))^x , where k is a constant, then P(X=0) is.

A random variable X takes the values 0,1,2,3,..., with probability P(X=x)=k(x+1)((1)/(5))^x , where k is a constant, then P(X=0) is.

The probability distribution of a random variable X taking values 1,2,3,4,5 is given c.Find the variance of X

The random variable X can take only the values 0,1,2. If P(X=0)= P(X=1)=p and E(X^(2)) = E(X), then find the value of p.

A random variable X takes the value -1,0,1. It's mean is 0.6. If P(X=0)=0.2 then P(X=1)=