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The young's double slit experiment is do...

The young's double slit experiment is done in a medium of refractive index `4//3`.A light of `600nm`wavelength is falling on the slits having `0.45` mm separation .The lower slit `S_(2)` is covered by a thin glass sheet of thickness `10.4mu m` and refractive index`1.5`.the intereference pattern is observed ona screen placed `1.5m` from the slits are shown

(a) Find the location of the central maximum (bright fringe with zero path difference)on the y-axis.
(b) Find the light intensity at point `O`relative to the maximum fringe intensity.
(c )Now,if `600nm`light is replaced by white light of range 400 to700 nm find the wavelength of the light that from maxima exactly point `O`.[All wavelengths in this problem are for the given medium of refractive index `4//3` .Ignore dispersion]

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A YDSE is performed in a medium of refractive index 4 // 3 , A light of 600 nm wavelength is falling on the slits having 0.45 nm separation . The lower slit S_(2) is covered b a thin glass plate of thickness 10.4 mm and refractive index 1.5. The interference pattern is observed on a screen placed 1.5 m from the slits as shown in figure. (All the wavelengths in this problem are for the given medium of refractive index 4 // 3 , ignore absorption.) Find the light intensity at point O relative t maximum fringe intensity.