Relation between the stopping potential `V_0` of a metal and the maximum velocity of the photoelectrons is

Relation between the stopping potential V_0 and a metal and the maximum velocity of the photoelectrons is

What is the relation between the stopping potential V_(0) and the maximum velocity v_("max") of photoelectrons?

If e/m of electron is 1.76xx10^(11)Ckg^(-11) and the stopping potential is 0.71 V, then the maximum velocity of the photoelectron is

if e/m of electron is 1.76xx10^(11)C(kg)^(-1) andn stopping potential is 0.71 V, then the maximum velocity of the photoelectron is

For a monochromatic radiation incident on a metal surface, the stopping potential is 2.0V. Find out the maximum velocity of the emitted photoelectrons.

For a monochromatic light incident on a metal surface, the maximum velocity of the emitted photoelectrons is v. Then the stopping potential would be

For a monochromatic light incident on a metal surface, the maximum velocity of the emitted photoelectrons is v. Then the stopping potential would be

For a monochromatic light incident on a metal surface, the maximum velocity of emitted photoelectrons is v. Then the stopping potential would be

How is the stopping potential in volt related to the maximum kinetic energy of photoelectrons in electron volt?

Photons of energy 2.0eV fall on a metal plate and release photoelectrons with a maximum velocity V . By decreasing lambda and 25% the maximum velocity of photoelectrons is doubled. The work function of the metal of the material plate in eV is nearly