A particle executes a linear S.H.M. of amplitude 8 cm and period 2s. The magnitude of its maximum velocity is

A body of mass 200 g is executing a S.H.M. of amplitude 50 cm and period 1 s. The magnitude of maximum force acting on the particle is (use pi^(2)=10)

A particle executes a linear S.H.M. of amplitude A and period T. It starts from the mean position. The time required to cover a dis"tan"ce A/2 is

particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds , then the maximum velocity of the particle will be

A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle exectues a linear S.H.M. of amplitude 2 cm. When it is at 1cm from the mean position, the magnitudes of its velocity and acceleration are equal. What is its maximum velocity ? [sqrt(3)=1.732]

A particle executes a S.H.M. of amplitude 4 cm and period 4 sec. If at time t=0, the net force acting on the particle is zero, then its velocity at that point is given by

A particle is executing SHM with an amplitude of 2 m. The difference in the magnitudes of its maximum acceleration and maximum velocity is 4. The time period of its oscillation is

A particle executing S.H.M. has an amplitude of I m and time period 2 s. The velocity when displacement being 0.5 m is

A particle executes S.H.M. of amplitude A . At what positions of its displacement (x), will its velocity be zero and maximum?

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.