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Equation of a line passing through (-1,2...

Equation of a line passing through `(-1,2,-3)` and perpendicular to the plane `2x+3y+z+5=0` is

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(i) Find the equation of the plane passing through (1,-1,2) and perpendicular to the planes : 2 x + 3y - 2z = 5 , x + 2y - 3z = 8 . (ii) find the equation of the plane passing through the point (1,1,-1) and perpendicular to each of the planes : x + 2y + 3z - 7 = 0 and 2x - 3y + 4z = 0 . (iii) Find the equation of the plane passing through the point (-1,-1,2) and perpendicular to the planes : 3x + 2y - 3z = 1 and 5x - 4y + z = 5.

Equation of a line passing through (1,-2,3) and parallel to the plane 2x+3y+z+5=0 is